Following are the results of my string computer exercise, including the effects of steering lock, using the formulae for camber induced by caster and kingpin inclination according to my preceeding post. The calculations are based on 7 degrees of caster and 10.9 degrees of kingpin inclination. These values seem to be in the ballpark for Miata and Corvette according to ‘Steve’ in my earlier post where I reported his formulae.
So, the question is: for those of you who have done this before, do my resulting cambers for the outer wheel look reasonable? The inner wheel seems to be a dead loss, but that seems consistent with everything I’ve read. Being a Naval Architect by profession, the only value in this table for which I have an intuitive appreciation is roll angle!
(My apologies for the unformatted Table, but I wanted to put it in the message body. The first column of each table is steering lock: 0, 5, 10, 15 and 20 degrees. The columns are cambers at various roll angles: 0,1,2, ..., 6 for zero bump, and 0,2,4,6 for 1 inch bump.)
Suspension in Roll, No Bump
Roll, deg 0 1 2 3 4 5 6
Lock, deg. Outer Wheel Camber, deg
0 0 0.5 1 1.4 1.75 2.1 2.5
5 -0.57 -0.07 0.43 0.83 1.18 1.53 1.93
10 -1.05 -0.55 -0.05 0.35 0.70 1.05 1.45
15 -1.44 -0.94 -0.44 -0.04 0.31 0.66 1.06
20 -1.74 -1.24 -0.74 -0.34 0.01 0.36 0.76
Lock, deg. Inner Wheel Camber, deg
0 0.00 0.70 1.50 2.30 3.00 3.80 4.50
5 0.65 1.35 2.15 2.95 3.65 4.45 5.15
10 1.38 2.08 2.88 3.68 4.38 5.18 5.88
15 2.18 2.88 3.68 4.48 5.18 5.98 6.68
20 3.05 3.75 4.55 5.35 6.05 6.85 7.55
Suspension in Roll, 1 in. Bump
Roll, deg 0 2 4 6
Lock, deg. Outer Wheel Camber, deg.
0 -1.00 -0.50 0.00 0.50
5 -1.57 -1.07 -0.57 -0.07
10 -2.05 -1.55 -1.05 -0.55
15 -2.44 -1.94 -1.44 -0.94
20 -2.74 -2.24 -1.74 -1.24
Lock, deg. Inner Wheel Camber, deg.
0 0.80 2.10 3.50 4.80
5 1.45 2.75 4.15 5.45
10 2.18 3.48 4.88 6.18
15 2.98 4.28 5.68 6.98
20 3.85 5.15 6.55 7.85
_________________
Warren
Isuzu Pickup/SR20DE, +401 COLD frame
Build Log:
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